Given a set of beliefs, what group of individuals make up its normal?
Negate beliefs that are more negative than positive in the population of individuals.
Start with an empty set of individuals.
Sort the individuals so that they are ordered from greatest agreement with the beliefs to least agreement with the beliefs.
Collect individuals into the set so long as the individual's addition increases that set's normalization metric.
Consider the following matrix (transposed from above →), flipping beliefs so that they are mostly affirmative:
P_1
P_2
P_3
P_4
P_5
Q1
1
1
1
0
0
!Q2
1
1
1
1
1
Q3
1
1
1
1
1
!Q4
1
0
0
1
1
!Q5
0
1
1
0
1
!Q6
0
1
1
1
1
Q7
0
1
0
1
1
Q8
1
1
0
1
0
Q9
1
1
1
1
1
Q10
1
1
1
0
1
!Q11
0
1
0
1
1
Now sort the individuals by their overall agreement:
P_2
P_5
P_4
P_1
P_3
Q1
1
0
0
1
1
!Q2
1
1
1
1
1
Q3
1
1
1
1
1
!Q4
0
1
1
1
0
!Q5
1
1
0
0
1
!Q6
1
1
1
0
1
Q7
1
1
1
0
0
Q8
1
0
1
1
0
Q9
1
1
1
1
1
Q10
1
1
0
1
1
!Q11
1
1
1
0
0
For the metric specified above, let us a table of what our answer could be [1], and what their normalization scores are.
[1]Individuals with equivalent agreement over the beliefs can be taken in any order. This means that there may be many answers to the question, which take the form "these N individuals, and M<P of these P individuals".
Set
Score
(P_2)
10
(P_2, P_5)
16.36
(P_2, P_5, P_4)
17.85
(P_2, P_5, P_4)+choose1(P_1, P_3)
15.14
(P_2, P_5, P_4, P_1, P_3)
12.05
It follows from this that our group contains the individuals P_2, P_5, and P_4.